Question

21g of CaO is obtained by roasting 50g CaCO3. What is the percentage yield of CaO? A. 25% B. 50% C. 75% D. 60% 200 I​

Answer 1

Answer:

The answer is option C:75%

Answer 2

Answer:

Option. C.

The percentage yield of CaO is 75%.

Given:

• mass of CaO is 21g.
• mass of CaCO3 is 50g.

To Find :

• the percentage yield of CaO =?

Solution:

The reaction is given by,

CaCO3 → CaO+ CO2

From the above reaction, we can say that when one mole of CaCO3 decomposed it gives one mole of Cal and one mole of CO2.

We know that,

Initial moles of CaCO3 = 50/100

= 0.5 mole

Also, moles of CaO produced are 0.5 moles.

Mass-produced during decomposition is

=0.5 × Molar Mass of CaO

= 28g

But the actual yield is 21g.

$percentage \: yield \: = (\frac{actual \: yied}{theoretical\: yield}) \times 100$

$= ( \frac{21}{28} ) \times 100$

= 0.75 × 100

= 75%

Hence the percentage yield of CaO is 75%.

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