21x^2-2x+1/21 factorise it.
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answer for the given problem is given
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21x^2-2x+1/21
we usually avoid factorising fractions!
so, multiply 21 to the equation
We will get
441x^2 - 42x+1
a*b = 1
a+b= -42
therfore
441x^2 - 21x-21x + (1)
=> (21x)^2 - 2 * 21x + +(1)^2
=> a^2 - 2ab + b^2 => (a-b)^@
=> (21x -1) ²
=>(21x -1)(21x - 1)
=> (x -1/21)(21x - 1)
hope it helps
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