Math, asked by adinawabganj, 9 months ago

21x^2-2x+1/21 factorise it.​

Answers

Answered by tennetiraj86
4

Answer:

answer for the given problem is given

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Answered by bagchigungun
0

Answer:

21x^2-2x+1/21​

we usually avoid factorising fractions!

so, multiply 21 to the equation

We will get

441x^2 - 42x+1

a*b = 1

a+b= -42

therfore

441x^2 - 21x-21x + (1)

=>   (21x)^2 - 2 * 21x + +(1)^2

=> a^2 - 2ab + b^2 => (a-b)^@

=> (21x -1) ²

=>(21x -1)(21x - 1)

=> (x -1/21)(21x - 1)

hope it helps

Step-by-step explanation:

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