Question

21x^2 = 4(2x+1)
Solve the quadratic equation

Answer 1

here's your answer ⭐

Answer 2

Answer:

=21x^2=8x+4

=21x^2-8x-4=0

=21x^2-(14x+6x) - 4=0

=21x^2-14x+6x-4=0

=3x(x-2) + 3 (x-2) =0 [21^2 and 14x multiply with 7 and 6x and 4 multiply with 2 ]

=(x-2) (3x+3)=0

IF : X-2=0

=X=2

EITHER : 3X+3=0

=X= -3/-3

Step-by-step explanation:

HOPE THIS WILL HELP YOU !