21x^2 = 4(2x+1)
Solve the quadratic equation
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Answer:
=21x^2=8x+4
=21x^2-8x-4=0
=21x^2-(14x+6x) - 4=0
=21x^2-14x+6x-4=0
=3x(x-2) + 3 (x-2) =0 [21^2 and 14x multiply with 7 and 6x and 4 multiply with 2 ]
=(x-2) (3x+3)=0
IF : X-2=0
=X=2
EITHER : 3X+3=0
=X= -3/-3
Step-by-step explanation:
HOPE THIS WILL HELP YOU !
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