Question

21x^2-8x-4=0 find the quadratic eq​

Answer 1

Answer:

» 21x² - 8x - 4 = 0

» 21x² - 14x + 6x - 4 = 0

» 7x (3x - 2) + 2 (3x - 2) = 0

» (3x - 2) (7x + 2) = 0

» x = 2/3 or x = -2/7

Answer 2

${21x}^{2} + 6x - 14x - 4 = 0 \\ 3x(7x + 2) - 2(7x + 2) = 0 \\ (7x + 2)(3x - 2) \\ ( x = - 2 \div7) \:( x = 2 \div 3)$