21x+47y =110
47x -21y =162
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use substitution method to solve
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Answer:
21x+47y=110......1.equ.
47x+21y=162.....2 equ
add equ 1 and 2
21x+47y=110
47x+21y=162
_________
68x+68y=272
divide equ by 68
x+y=4.....equ.3
subtract equ 1 from 2
47x+21y=162
21x+47y=110
_________
26x-26y=52
divide equ by 26
x-y=2.....equ4
add equ no 3 and 4
x+y=4
x-y=2
____
2x= 2
x=2/2
x= 1
substitute x value in equ 3
x+y=4
1+y=4
y=4-1
y=3
solu:(x,y)=(1,3)..
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