Question

21x² - 83x+34 solve it​

Answer 1

Step-by-step explanation:

21x^2+83x-34 =0

Step1: Divide all terms by the coefficient of x2 which is 21.

x 2 + 83 21 x − 34 21 = 0

Step 2: Keep all terms containing x on one side. Move the constant to the right.

x 2 + 83 21 x = 34 21

Step 3: Take half of the x-term coefficient and square it. Add this value to both sides.

x 2 + 83 21 x + 83 42 21 = 34 21 + 83 42 21

Step 4: Simplify right hand sides of expression.

x 2 + 83 21 x + 83 42 2 = 9745 1764

Step 2: Write the perfect square on the left.

x + 83 42 2 = 9745 1764

Step 2: Take the square root on both sides of the equation.

x + 83 42 = ± 9745 1764

Step 2: solve for root x1.

1 = − 83 42 + 98.7167665597 42 = 15.7167665597 42

x 1 = 0.374208727612

Step 2: solve for root x2.

x 2 = − 83 42 − 98.7167665597 42 = -181.71676656 42

x 2 = -4.32658967999

hope it's helpful