Math, asked by rasikadhuri1999, 7 months ago

22
14. A cetan sum of money is divided among A, B and
C such that A gets half of what B and C together
get B gets one-third of what A and C together get. If
A gor 2500 more than B, then how much money was
23​

Answers

Answered by SamVarghese
0

Step-by-step explanation:

let the money divided be X

X=A+B+C

given that A=1/2(B+C)

2A=B+C

C=2A-B--------(1)

Given that B=1/3((A+C)

3B=A+C

C=3B-A-------(2)

Also given that A=B+2500-------(3)

from (1) and (2)

2A-B=3B-A

2A+A=3B+B

3A=4B

A=(4/3)B

Substitute in (3)

(4/3)B=B+2500

(4/3)B-B=2500

4B-3B=3×2500

B=7500

A=(4/3)*7500

A=10000

C=2*10000-7500

C=12500

So the money divided X=10000+7500+12500

=Rs. 30,000

Similar questions