Question

22. 15x + 2x - 8 = 0 Solve the following quadratic equations:

Answer 1

Answer:

it is not a quadratic equation

Answer 2

Question :-

$15 {x}^{2} + 2x - 8 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$15 {x}^{2} + 2x - 8 = 0 \\ \\ 15 {x}^{2} + 12x - 10x - 8 = 0 \\ \\ 3x(5x + 4) - 2(5x + 4) = 0 \\ \\ (5x + 4)(3x - 2) = 0$

Now split it into possible cases

$(5x + 4) = 0 \\ \\ (3x - 2) = 0$

Hence,

$x_1 =( - \frac{4}{5} ) \\ \\ \\ x_2 = ( \frac{2}{3} )$

Extra information :-

• an equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).