Question

22✓2a³+8b³-27c³+18✓2abc​

Answer 1

$\Large{\underline{\underline{\bold{✯Given:}}}}$

• $2 \sqrt{2} {a}^{3} + 8 {b}^{3} - 27 {c}^{3} + 18 \sqrt{2} abc$

$\Large{\underline{\underline{\red{\bold{➸To\;Find:}}}}}$

• Factorisation.

$\Large{\underline{\underline{\bold{\color{salmon}๛Required\; Response:}}}}$

WKT

$\pink{\bf{a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)}}$

The Required Can Be Written As

• 2√2 = (√2)³
• 8 = 2³
• 27 = 3³

Here, a = √2a, b = 2b & c = -3c

Thus,

$2\sqrt{2} a^{3} + 8 {b}^{3} - 27 {c}^{3} + 18abc =$

$→\;{\sf{( \sqrt{2} a + 2b - 3c) [{( \sqrt{2}a) }^{2} + {(2b)}^{2} + {( - 3c)}^{2} -(\sqrt{2} a)(2b) - (2b)( - 3c) - ( - 3c)( \sqrt{2} a)]}} \\→\;{\sf{ ( \sqrt{2} a + 2b - 3c)(2 {a}^{2} + 4 {b}^{2} + 9 {c}^{2} - 2 \sqrt{2} ab + 6bc + 3 \sqrt{2} ca)}}$

Required Value

• $☞\;\blue{\bold{ ( \sqrt{2} a + 2b - 3c)(2 {a}^{2} + 4 {b}^{2} + 9 {c}^{2} - 2 \sqrt{2} ab + 6bc + 3 \sqrt{2} ca)}}$

✍ ɱσɾε เɳƒσɾɱαƭเσɳ:

• $\red{\bold{Refer\;The\; Attachment}}$ ⤴️

$\boxed{\tt{@MrMonarque}}$

Hope This Helps!!

Answer 2

Answer:

The upper and is right Mark him as brainliest