Question

22-3*[5+3*{(7-9)-2}]+10

Answer 1

Answer:

$\huge \boxed{41}\checkmark$

Step-by-step explanation:

Order of operations

PEMDAS

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Parenthesis first.

$\displaystyle (7-9)=-2$

$\displaystyle 5+3(-2)-2$

Multiply from left to right.

$\displaystyle5-6-2$

Subtract from left to right.

$\displaystyle 3(-2)=-6$

$\displaystyle 5-6-2=-3$

$\displaystyle 22-3(-3)+10$

Multiply from left to right.

$\displaystyle 3(-3)=-9$

$\displaystyle22-(-9)+10$

Add and subtract from left to right to find the answer.

$\displaystyle22+9=31+10=41$

$\huge \boxed{41}$, which is our answer.

Answer 2

Answer:

41 is your answer.

Step-by-step explanation:

Given Problem:

$22-3\times[5+3\times{(7-9)-2}]+10$

Solution:

To Do:

Simplify it:

$22-3\times[5+3\times{(7-9)-2}]+10$

-------------------------------

Method:

We know that,

PEMDAS rule.

Where,

P = Parenthesis.

E = Exponent.

M = Multiplication.

D = Divide.

A = Addition.

S =Subtraction.

According to PEMDAS rule:

First solve Parenthesis:

$\implies\ (7-9) = -2$

$\implies\ 5+3(-2)-2$

Now, Multiply from left to right:

$\implies\ 5-6-2$

Now, Subtract from left to right,

$\implies\ 3(-2) = -6$

$\implies\ 5-6-2 = -3$

$\implies\ 22-3(-3)+10$

Now,Multiply,

$\implies\ 3(-3) = -9$

$\implies\ 22-(-9)+10$

Add and subtract from left to right to find the answer,

$\implies\ 22+9=31+10=41...............(Answer)$