Question

22/7 upto 3 decimal places and its formula.​

Answer 1

Answer:

For the first triangle, we have

a=35 , b=53 , and c=66

∴s=

2

a+b+c

=

2

35+53+66

=77cm

now ,

Δ

1

= Area of the first triangle

⇒Δ

1

=

s(s−a)(s−b)(s−c)

⇒Δ

1

=

77(77−35)(77−53)(77−66)

=

77×42×24×11

7×11×7×6×6×4×11

=

7

2

×11

2

×6

2

×2

2

⇒Δ

1

=7×11×6×2=924cm

2

For the second triangle , we have

a=33,b=56,c=65

∴s=

2

a+b+c

=

2

33+56+65

=77cm

Area of the second triangle

⇒Δ

1

=

s(s−a)(s−b)(s−c)

⇒Δ

1

=

77(77−33)(77−56)(77−65)

=

77×44×21×12

⇒Δ

1

=

7×11×4×11×3×7×3×7

⇒Δ

1

=

7

2

×11

2

×4

2

×3

2

=7×11×4×3=924cm

2

Let r be the radius of the circle . Then

Area of the circle = sum of the area of two triangles

Area related to circles

⇒πr

2

=Δ

1

+Δ

2

⇒πr

2

=924+924

⇒

7

22

×r

2

= 1848

⇒r

2

=1848×

22

7

=3×4×7×7⇒r=

3×2

2

×7

2

=2×7×

3

=14

3

cm