Question

22. A battery of e.m.f. 10 V is connected to resistance
as shown in figure. The potential difference VA - VB
between the points A and B is​

Answer 1

Answer:

and is 2 by my knowledge

in A,B r in lle combination. A- has 2 ristors 1,3 in series connection so,

4r series connection form is

#R eq= R1+ R2±.....

4r lle combination the form is

#Req=R1R2/R1+R2

SO,let's apply it to the A res..t

R(a)=1+3=4 ,smillrly

R(b)=3+1=4

then, lle combination A,B. so,

R1R2/R1+R2. i.e. => 4*4/4+4=16/8=2

then , here the battery is connected with 1more rest..or 3ohms so they are series connection

same ,

R=3+2=5

The

Req=5 , then acc to ohms law

v=IR =>I=v/R

v=10, R=5

10/5=2 so the, potential difference is 2

like if u like it......!:)

Answer 2

Answer:

2v

Explanation:

Equivalent resistance = 5ohm

v = iR

i = 10/5= 2A

potential at A

= 1*1= 1v

potential at B

= 3*1= 3v

Va - Vb = 2v