Question

22. A body of mass m is placed on the earth surface.
It is taken from the earth's surface to a height h =
3R. The change in gravitationak potential energy
of the body is​

Answer 1

Answer:

answer is 3/4 mgR

Explanation:

Δu=mgh/1+(h/R)

    =(mg×3R)/(1+3R/R)

    =3/4mgR