Question

22. A car starts from rest and moves along the x-axis with constant
acceleration
5 ms-' for 8 seconds. If it then continues with constant velocity, what
distance will the car cover in 12 seconds since it started from the rest?
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Answer 1

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u = 0 m/s acc = 5 t = 8 sec

v = u + at

v = 0 + 5 × 8

v = 40 m/s

Now distance when t = 12 sec

$s = ut + \frac{1}{2} a {t}^{2}$

s = 0 + 1/2 × 5 × 12 × 12

s = 5 × 6 × 12

s = 360 m

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Answer 2

Answer:

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Explanation:

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