22. A circular garden of radius 15m has a 2m wide circular path inside arround it. Find the area of the
path.
23. Find the radius of a sphere whose surface area is 616 cm2
.
24. Evaluate : Cos 43o
. Cot 79o
– Sin 47o
. tan 11o
25. A pole of height 6 m casts shadow of 2 3 m on the ground. Find the Sun’s elevation.
26. Evaluate a3
+b3
, if a+b = 7 and ab = 12.
Answers
Answered by
3
22 ) Let the radius of outer circle be (R ) = 15 cm
so the radius of inner circle (r) = 15-2 =13 cm
area of path =22/7 ( 225- 169)
= 22/7 × 56
= 22×8 = 176
so the radius of inner circle (r) = 15-2 =13 cm
area of path =22/7 ( 225- 169)
= 22/7 × 56
= 22×8 = 176
Answered by
0
25. tan ø =6/23. where theta is the angle of elevation of sun. Therefore in order to find the angle of elevation of sun we have to calculate the tan inverse of 6/ 23 which is 14.6°. Hence the angle of elevation of sun is 14.6° . Hope this answer helped you. I never ask for marking as brainliest. please just follow .
vquantumv:
26- a^3 + b^3 = (a+b) (a^2+ab+b^2)
value of a and b ?
they are variables no matter what value you put of a or b The Identity will be satisfied in every case
hope you understood
yes , you are right
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