Question

22. A line L cuts the sides AB, BC of AABC in the
ratio 2 : 5, 7 : 4 respectively. Then the line L
cuts CA in the ratio
1) 7: 10 2) 7:-10 3) 10:7 4) 10 :-7​

Answer 1

Answer:

Step-by-step explanation:

Hope u got it.if any doubts please ask in comment section

Answer 2

Answer:

$\frac{CE}{EA}\ =\ \frac{10}{7}$

Step-by-step explanation:

As per the question,

We have been given that

A line L cuts the sides AB and BC at point F and D respectably in ΔABC

value of AF = 2, FB = 5, BD = 7 and DC = 4

If line L cuts in the side AC at point E then find the value of EA and CE

therefore, $\frac{BD}{DC}\times \frac{CE}{EA}\times \frac{AF}{FB}$  = 1

$\frac{7}{4}\times \frac{CE}{EA}\times \frac{2}{5}$  = 1

$\frac{CE}{EA}\times \frac{7}{10}$  = 1

$\frac{CE}{EA}$  = $\frac{10}{7}$

$\frac{CE}{EA}\ =\ \frac{10}{7}$

Hence, value of  $\frac{CE}{EA}$  = $\frac{10}{7}$