Question

22. A particle is in uniform circular motion with speed
V. The change in magnitude of velocity when it
covers half of circular path is​

Answer 1

If v is velocity at a point then v is in the direction of tangent to the circular path at that point. When particle completes half the circle it reaches the diagonally opposite point where the direction of tangent is opposite. Hence, if we call velocity at first point as+v, it is-v at the other point. The difference or change =-v-(+v)=-2v.

Answer 2

Answer:

0 m/s

Explanation:

Given that velocity of particle is uniform.

Lets take uniform speed = v m/s

The speed of the particle at point A is v j then the magnitude of velocity will be v.

The speed of the particle at point B is -v j then the magnitude of velocity will be v.

So

Change in magnitude of velocity when it  covers half of circular path = v-v

                                                                                                                   = 0 m/s

So the answer is 0 m/s.