Question

22. A particle is rotating on a circular path with initial
angular velocity 2 rad/s and angular acceleration
of 1 rad/s2 then find its net acceleration in m/s after
2 s (radius of path) is 1 m :-
(1) 257
(2) /17
(3) 1
(4) 16​

Answer 1

Answer:

root17

Explanation:

anet=underroot centripetal acceleration +tangential acceleration

centripetal acceleration =rw²=1×4=4

tangential acceleration =ralpha=1×1=1

anet=underroot 4²+1²=underroot 16 +1=root 17

Answer 2

The correct answer of the following question is $\sqrt{17$, so the correct option is (2)

Given: angular velocity = 2 rad/sec

           angular acceleration = 1 rad/sec

           time = 2 second

           radius of the path = 1m

To find: net acceleration

Solution:

Net acceleration = $\sqrt{(centripetal acceleration)^2+ (tangential acceleration)^2$  

Centripetal acceleration = rω²

                                         = 1×4 = 4

Tangential acceleration = rα

                                        = 1×1 = 1

Therefore, the net acceleration = $\sqrt{(4)^2 + 1^2$

                                                     = $\sqrt{17$

Therefore the correct option is (2)