Math, asked by shibam231, 7 months ago

22
A shopkeeper sells a table at 8% profit and a chair at 10% discount, thereby getting
1008. If he had sold the table at 10% profit and chair at 8% discount, he would have
got 20 more. Find the cost price of the table and the list price of the chair.
A
and Bhara
ar​

Answers

Answered by pari2008chitra61
0

Answer:

ANSWER

Given,

Profit on table =8%

Discount on chair =10%

Let

C.P. of table = Rs x and

C.P. of chair = Rs y

Then according to the question,

100

x×(100+8)

+

100

y×(100−10)

=1008

⇒108x+90y=100800

⇒6x+5y=5600 … (i)

And,

100

x×(100+10)

+

100

y×(100−8)

=1008+20

⇒110x+92y=102800

⇒55x+46y=51400 … (ii)

Now, multiplying (i) by 55 and (ii) by 6, we have

330x+275y=308000 ... (iii)

330x+276y=308400 ... (iv)

Subtracting equation (iv) from (iii), we get

−y=−400

⇒y=400

On substituting the value of y in equation (i), we get

6x+5(400)=5600

⇒6x=5600−2000

⇒x=

6

3600

⇒x=600

Hence,

Cost Price of the table = Rs 600

List price of chair =400×

100

90

= Rs 360

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