Question

22. A stone of mass 0.25 kg is tied to a string of 1 m radius. It is swung round in a
horizontal circle. The maximum tension the string can withstand is 100N.
Calculate (a) the angular velocity (b) the speed of rotation and (c) the number of
revolutions per minute, just before snaps.​

Answer 1

Answer:

answer is attached in the image below

Answer 2

Data:

m = 0.25kg

l = r = 1m

T = 100N

SOLUTION:

In this Question the T = Fc

mv²/r = T

0.25 ×v² = 100r

v² = 100/0.25

v = 20m/s(Linear velocity)

v = rw => w = v/r

w = 20/1 = 20rad/s(angular Velocity)

w = 20/(2π×60)

w = 0.05 rev/ min