Question

22. A students scored a total of 32 marks in class tests in mathematics and science. He had scored 2

marks less in science and 4 more in mathematics, the product of his marks would have been 253.

Find his marks in two subject​

Answer 1

Answer:

Step-by-step explanation:

Let the marks in Maths be 'm' & marks in science be 's'

Given,m + s = 32

If he had scored 2 marks less in science, that is, (s-2) and 4 marks more in maths, that is (m+4), then the product equals 253

(s-2)*(m+4) = 253

 Substitute s = 32-m for 's' in above equation

(32-m-2)*(m+4) = 253

(30-m)*(m+4) = 253

30m - m^2 - 4m + 120 = 253

26m - m^2 = 133

m^2 - 26m + 133 = 0

m^2 - 19m - 7m + 133 = 0

m(m-19) - 7(m-19) = 0

(m-7)(m-19) = 0

So m = 19 OR 7

If m = 19, s = 32-19 = 13

If m = 7, s = 32-7 = 25

Both the marks satisfy the given condition

So the marks are either (Maths=19, Science=13) or (Maths=7, Science = 25)

pls mark it as a brainliest answer.

Answer 2

Answer:

Maths mark = 7 or 19

science mark = 25 or 13

Step-by-step explanation:

let keep maths mark = x

science mark = 32 - x

He had scored 2 marks less in science and 4 more in mathematics

(32 - x - 2)(x + 4 ) = 253

(30 - x ) ( x + 4 ) = 253

solving we get

x = 7 & x = 19

If x = 7

Maths mark = 7

science mark = 25

If x = 19

Maths mark = 19

science mark = 13