Question

22. (a2 + b2 – 4c2)2 – 4a2b2
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Answer 1

Answer:

(a^2+b^2-4c^2)^2 - (2ab)^2

((a^2+b^2-4c^2 + 2ab)(a^2+b^2 -4c^2-2ab)

((a+b)^2-(2c)^2)((a-b)^2-(2c)^2)

(a+b+2c)(a+b-2c)(a-b+2c)(a-b-2c) Ans