22 and 23
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Answers
Answer:
22. a)9. b)4. c)16.
22). a). 1/r= 1/6+1/6
r=3
eq. resisitance=6+3=9
b). r=6+6=12
1/eq.resistance =1/12+1/6=3/12
eq. resistance =4
23) r=6+6=12
1/r=1/12+1/6
r=4
eq. resistance= 6+6+4=16
h
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Answer:
It is very simple bro:
22. a) Two 6 ohm resistor are in parallel then,
their total resistance will be
1/R1 = 1/6 + 1/6
1/R1 = 2/6
R1 = 6/2
R1 = 3 Ohms
Now, total resistance of the circuit will be
= 3+6= 9 ohms ✔️
b) Two resistance of 6 ohms are in series with a 6 ohms resistor
Equivalent resistance of the the series resistor = 6 + 6 = 12 ohms
Now, Total resistance of the circuit
1/R = 1/6 + 1/12
1/R = 2+1/12
1/R = 3/12
R = 12/3
R = 4 ohms✔️
23. First two 6 ohms resistor are in series and parallel with another 6 ohms resistor and then are in series.
Now, R1 = 6 + 6 = 12 ohms
1/R2 = 1/6 + 1/12
1/R2 = 2+1/12
R2 = 12/3 ohms
R2 = 4 ohms
Now, resistance between A and B is
= 6+6+4 ohms
= 16 ohms✔️
This may help you