Question

22.
At a given temperature, the equilbrium
constant for the reaction
PCI5 (g) = PCl3(g) + Cl2 (g)
is 2.4 x 10-3. At the same temperature, the
equilibrium constant for the reaction.
PCl3(g) (g) + Cl2 (g) = PCl5, (g) is
(a) 2.4 x 10-3 (b) -2.4 x 10-3
(c) 4.2 × 102(d) 4.8 × 10-2

​

Answer 1

a) 2.4*10-3 is it the answer

Answer 2

The  equilibrium constant for the reaction $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$ is $</strong>4.2\times 10^2$    

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is:

$PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)$

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}$

$2.4\times 10^{-3}=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}$

For the reverse reaction:

$PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

The expression for equilibrium constant for this reaction will be,

$K_c'=\frac{[PCl_5]^1}{[PCl_3]^1[Cl_2]^1}$

$K_c'=\frac{1}{K_c}=\frac{1}{2.4\times 10^{-3}}=4.2\times 10^2$    

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