22. C2H5l on reduction in presence of
Zn/HCl gives
O Propane
Methane
Ο Ο Ο Ο
Pentane
Ethane
Answers
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Answer:
Ethane
Explanation:
C2H5I +2H--------Zn/HCl----->C2H6+HI
It is called reduction of alkyl halide.
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