Math, asked by ranjansinghishu11198, 3 months ago


22. Chandani purchased some parrots. 20% flew away and 5% died. Of the remaining,
were sold. Now 33 parrots remain. How many parrots had Chandani purchased?​

Answers

Answered by shreyamamatha60
3

Answer:

80

Step-by-step explanation:

Answer

Consider Chandani purchased x parrots

No. of parrots flew away =20% of x

It can be written as

=20/100×x

So we get

=1/5×x

=x/5

No. of parrots died =5% of x

It can be written as

=5/100×x

=x/20

No. of parrots remaining = x−(x/5+x/20)

Taking LCM

=x−[(4x+x)/20]

By further calculation

=x−5x/20

=x−x/4

Taking LCM

=3x/4

No. of sold parrots = 45% of 3x/4

It can be written as

=45/100×3x/4

By further calculation

=9/20×3x/4

=27x/80

No. of parrots which are not sold =3x/4−27x/80

Taking LCM

=(60x−27x)/80

=33x/80

Based on the question

33x/80=33

By cross multiplication

33x=33×80

So we get

x=(33×80)/33

x=80

Therefore, Chandani purchased 80 parrots.

Hope this helps

Answered by lspsjk
7

Answer:

Consider Chandani purchased x parrots

No. of parrots flew away =20% of x

It can be written as

=20/100×x

So we get

=1/5×x

=x/5

No. of parrots died =5% of x

It can be written as

=5/100×x

=x/20

No. of parrots remaining = x−(x/5+x/20)

Taking LCM

=x−[(4x+x)/20]

By further calculation

=x−5x/20

=x−x/4

Taking LCM

=3x/4

No. of sold parrots = 45% of 3x/4

It can be written as

=45/100×3x/4

By further calculation

=9/20×3x/4

=27x/80

No. of parrots which are not sold =3x/4−27x/80

Taking LCM

=(60x−27x)/80

=33x/80

Based on the question

33x/80=33

By cross multiplication

33x=33×80

So we get

x=(33×80)/33

x=80

Therefore, Chandani purchased 80

this is the answer

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