Math, asked by meenakumari04841, 3 months ago

22. Construct a quadrilateral PQRS in which PQ = 7.2 cm. QR = 6.4 cm. ZPQR = 90
PRS= 1204 and RS = 4.5 cm. (write the steps of construction)​

Answers

Answered by jaimohanvt
1

Step-by-step explanation:

Construct a line segment PR = 6.5 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilatera

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