Question

22. Find 4 rational numbers between-4/7 and 1/7​

Answer 1

Answer:

Your answer is 5/28, 6/28, 7/28, 8/28, 9/28.

Step-by-step explanation:

LCM of 7 and 4= 28

1/4=4/28 , 7/4=49/28.

So, five rational numbers are:

5/28, 6/28, 7/28, 8/28, 9/28.

Answer 2

Answer:

4 rational numbers between (-4/7) and 1/7 are

$( - \frac{3}{7} ),( - \frac{2}{7} ),( - \frac{1}{7} ),( \frac{0}{7} )$

Step-by-step explanation:

Here given two fractions are $- \frac{4}{7}$ and$\frac{1}{7}$

We want to find four rational number between given two rational numbers.

But question is what is rational number?

Any number that can be written as a fraction of two integers is called a rational number.

Here first we need to make denominator same of both fraction.

Now, four rational numbers between $( - \frac{4}{7} )$ and $( \frac{1}{7} )$

are $( - \frac{3}{7} ),( - \frac{2}{7} ),( - \frac{1}{7} ),( \frac{0}{7} )$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549