Question

22. Find the least number which when divided by 14, 42 and 28 leaves remainder 3 in each case​

Answer 1

$The \: least \: number \: which \: when \: divided \: by \: 14, 42 \: and \: 28 \: leaves \\remainder \: 3 \: in \: each \: case$

$= L.C.M ( 14 , 42 , 28 ) + remainder$

Finding L.C.M ( 14,42,28) :

2 | 14 , 42,28

___________

7 | 7 , 21 , 14

___________

*** 1 , 3, 2

LCM ( 14, 42, 28 )

= 2×7×1×3×2

= 84

******************************

$= 84 + 3 \\= 87$

Therefore.,

$\red{ Required \: least\: number } \green { = 87 }$

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Answer 2

Answer:

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