Question

22. Find the least number which when divided by 25, 40 and 60 leaves 9 as the remainder
Cách Case,
ther of five digits that is exactly divisible by 16, 18, 24 and 30.
and 24​

Answer 1

For finding the least number which when divided by 25, 40 and 60 leaves 9 as the remainder

each case, we have to find there L.C.M.

L.C.M. = 1200.

The required number = 1200 + remainder = 1200 + 9 = 1209

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