Question

22. Find the zeros of 6x²-3-7x and verify the relationship between
the xeros and the coefficients​

Answer 1

Answer:

6x² - 7x -3

6x² - ( 9-2)x -3

6x² - 9x+2x -3

3x ( 2x - 3 ) + 1 (2x-3)

2x-3=0 , 3x+1=0

x= 3/2. , x= 1/3

Answer 2

Answer:

x= -1/3 and x= 3/2

Step-by-step explanation:

6x²-7x-3=0

6x²+2x-9x-3=0

2x(3x+1)-3(3x+1)=0

(3x+1) (2x-3) =0

therefore, 3x+1=0 or 2x-3=0

x=-1/3 or x=3/2

Verification:

alpha+ß = -1/3+3/2

= -2+9/6

= 7/6

-b/a = -(-7)/6

= 7/6

therefore , alpha+ß=-b/a

alphaß = (-1)(3)/(3)(2)

=-1/2

c/a = -3/6=-1/2

therefore, alphaß= c/a