Question

22.find the zeros of the given quadratic plynomial and verify the relationship between zeros and the cofficent
$6x + x - 12$
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Answer 1

Answer:

{ - $\frac{3}{2}$ , $\frac{4}{3}$ }

Step-by-step explanation:

I assume that the quadratic polynomial is 6x² + x - 12

6x² + x - 12 = 0

D = b² - 4ac = 1² - 4(6)( - 12) = 289 = 17²

$x_{12}$ = ( - b ± √D ) / 2a = ( - 1 ± 17 ) / 2(6)

$x_{1}$ = $\frac{4}{3}$

$x_{2}$ = - $\frac{3}{2}$