Question

22] from a quadratic polynomial whose zeros
are 3+√2 and 3√-2​

Answer 1

Step-by-step explanation:

$\huge\fcolorbox{red}{yellow}{Hello}$

Zeros : 3 + √2 ; 3 - √2

General Form of a Quadratic Equation: ax² + bx + c

Here b is the sum of roots, c is the product of roots.

Sum of roots is taken as negative value.

That is,

=> x² - ( sum of roots ) x + product of roots.

According to your question,

Sum of roots = 3 + √2 + 3 - √2

=> Sum of roots = 6

Product of roots = ( 3 + √2 ) ( 3 - √2 )

=> Product of roots = 3² - ( √2 )²

=> Product of Roots = 9 - 2 = 7

Hence on substituting the values we get,

=> x² - ( 6 ) x + 7

=> x² - 6x + 7

This is the required equation

$<svg width="200" height="300" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="Red" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

Answer 2

Answer:

the above answer is correct