Question

22 g of water at 30° C is mixed with an equal amount of water at 60°C. Then find the resultant temperature of the mixture.​

Answer 1

Answer:

45° C

Explanation:

let the final temperature be T

heat lost  = heat gain

heat lost  = m x s x (60-T)

heat gain = m x s x (T-30)

m =22g s=specific heat capacity of water

$ms(60-T)=ms(T-30)\\60-T=T-30\\2T=90\\T=45$