Question

22. (i) sin (90° - 0). cot (90° - 0) = sin 0​

Answer 1

Solution:-

$\implies \sin(90 - 0). \cot(90 - 0) \\ \\ \\ \implies \cos \: 0. \tan \: 0 \\ \\ \implies \: 1 \times 0 \\ \\ \implies \: 0 \\ \\ \implies \red{ 0 = \sin \: 0} \: \: hence \: proved$

formula uses

$\implies \pink{ \sin(90 - \theta) = \cos \theta } \\ \\ \implies \pink{\cot(90 - \theta) = \tan \theta} \\ \\ \\ \implies \pink{\tan \: 0 = 0} \\ \\ \implies \pink{\cos \: 0 = 1} \\ \\ \implies \pink{ \sin \: 0 = 0}$

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