Question

22. If a fraction's denominator is decreased by
80% and numerator is increased by 300%,
the fraction becomes 2/9. What is the
fraction?
b. 6/45
d. 6/72
a. 8/9
c. 1/90​

Answer 1

$Let \: the \: numerator \: of \: the \:fraction=x$

$the \: denominator \: of \: the \:fraction=y$

$\red{The \: fraction = \frac{x}{y} \: --(1)}$

/* According to the problem given */

denominator is decreased by

denominator is decreased by80% and numerator is increased by 300%,

numerator is increased by 300%,the fraction becomes 2/9

$\frac{x\Big( \frac{100+300}{100}\Big)}{y\Big( \frac{100-80}{100}\Big)}= \frac{2}{9}$

$\implies \frac{ x \Big( \frac{400}{100}\Big)}{ y \Big( \frac{20}{100}\Big) } = \frac{2}{9}$

$\implies \frac{400x}{20y} = \frac{2}{9}$

$\implies \frac{20x}{y} = \frac{2}{9}$

$\implies \frac{x}{y} = \frac{2}{20\times 9}$

$\implies \frac{x}{y} = \frac{1}{10\times 9}$

$\implies \frac{x}{y} = \frac{1}{90}$

Therefore.,

$\red{ Required \:fraction } \green { = \frac{1}{90} }$

$Option \: \pink { ( c ) } \: is \: correct.$

•••♪

Answer 2

Answer:

the answer is 1/90

Step-by-step explanation:

let numirator be x and denometer be y.

by increasing numerator it becomes 3x

and by decreasing denomenator it becomes y/5

A/Q