.22.if AUB=AUB, prove that A = B?
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Step-by-step explanation:
Prove: (A∪B=A∩B)⟹(A=B)
Suppose x∈A, then x∈A∪B. So then x∈A∩B. Thus x∈B and thus A⊆B
Suppose x∈B, then x∈A∪B. So then x∈A∩B. Thus x∈A and thus B⊆A
Therefore, A=B
Is this correct? Another way to prove this? tips for a better proof writing?
Step-by-step explanation:
An other way
A⊂A∪B=A∩B⊂A
and
B⊂A∪B=A∩B⊂B.
Therefore
A=A∪B=A∩B=B.A simple proof by contradiction, A≠B, then either:
∃x:x∈A∧x∉B
∃x:x∈B∧x∉A
Let's look at 1 (2 is symmetrical). From 1 ⇒x∉A∩B which means (from A∩B=A∪B assumption) x∉A∪B which is a contradiction (with A∪B={x:x∈A∨x∈B}).
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