Question

22.
If K.E. body is increased by 100%. Then % change
in 'P'.
(2) 41.4%
(1) 50%
(3) 10%
(4) 20%​

Answer 1

Explanation:

Linear momentum P=

2mK

Final kinetic energy K

f

=2K

So, final momentum P

f

=

2mK

f

=

4mK

Percentage change in momentum

P

P

f

−P

×100=

2mK

4mK

−

2mK

×100

So,

P

P

f

−P

×100=

2

4

−

2

×100=41.4%