Question

22. If p = -10, evaluate :
(0) 6p + 50
(ii) 3p2 - 20p
(iii​

Answer 1

Answer:

P= -10

Thus,

$6p + 50 \\ \\ = 6 \times ( - 10) + 50 \\ = - 60 + 50 \\ = -10$

ii)

$3p {}^{2} - 20p \\ \\ = 3 \times ( - 10) {}^{2} - 20 \times ( - 10) \\ = 300 + 200 \\ = 500$

Answers are -10 and 500

Answer 2

$p = - 10 \\ \\ 6p + 50 = 6( - 10) + 50 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = - 60 + 50 \\ = - 10 \\ \\ 3 {p}^{2} - 20p = 3 \times { - 10}^{2} - 2 \times ( - 10) \\ \\ = 100 \times 3 + 20 \\ \\ = 300 + 20 \\ \\ = 320$

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