Question

22. If p(x) = (x-1)(x+1); Find p(1)
C​

Answer 1

Answer:

4562

Step-by-step explanation:

Answer 2

Answer:

$p(x) = (x - 1)(x + 1) \\ p(1) = (1 - 1)(1 + 1) \\ p(1) = (0)(2) \\ p(1) = 0 \times 2 \\ = 0$

therefore the p(1) is the zeros of the polynomial