Question

22. If the function f : (2,6) → (-1,6) is
defined by f(x) = x² - 4x + 3 then
f'(x)=
​

Answer 1

If f(x)=x^2 −4x+3

F(2)=2^2 −4(2)+3

=4−8+3

=−4+3

=−1

F(1)=(1)^2 −4+3

=1−4+3−3+3

=0

F(2)−F(1)

=−1+0

=−1