Question

22) If the perimeter of a triangle is 17cm and the sides are 3x +1, 2x + 1 and x + 3, find x
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Answer 1

here perimeter of triangle is 17 cm
(3x+1)+(2x+1)+(x+3)=17
3x+2x+x+1+1+3=17
6x+5=17
6x=17-5
6x=12
x=12/6
x=2

therefore the value of x is 2

Answer 2

If the perimeter of a triangle is 17 cm and its sides are 3x + 1, 2x + 1 and x + 3, then,

(3x + 1) + (2x + 1) +(x + 3) = 17cm

6x + 5 = 17cm

6x = 17 - 5

6x = 12

x = 12 ÷ 6

x = 2

So, The value of x = 2