Question

22. If x=2√6÷(√3+√2)
then the value of
(x+√2/x-√2)+(x+√3/x-√3)​

Answer 1

Answer:

x = (2√6) / (√3 + x2)

x + =2 = 2√6 / (()3 + √2) +

= 2 = (2√6 + +6 +2) / (√3 +2) √2)

= (3√6 + 2) / ((+3 + x2)

x-√2 = (2√6 -√6-2)

= (√6 -2)

(x + √2) / (x) -√2) = (3√6 + 2) / (-26-2)

Then,

(x + √3) = (2 +6 + 3 + )6)

= (3√6 + 3)

(x-( ) 3) = (2 )6-3-√6)

= (-36-3)

(x + √3) / (x-x3) = (3√6 + 3) / (√6-3)

(x + ) √2) / (x -√2) + (x + )3) / (x-)3)

= (3 )6 + 2) / (√6-2) + (3√6 + 3) / (() 6-3)

= {18 + 2√6 -9-6-6 + 18 + 3-6-6√6-6} / ((/6-2) (-36-3)

= {36-12 -10 √6} / (6-5√6 + 6)

= (24-10 ) 6 ) / (12-5√6)

= 2 (Ans)