Question

22.
If (x + a) is a factor of 2x2 + 2ax + 5x + 10, find 'a'.​

Answer 1

Answer:

a=-2

Step-by-step explanation:

factor is (x+a)

so x=-a

putting the value of x in p( x)

2x^2+2ax+5x+10

2a^2-2a^2-5a+10

-5a+10=0

-5a=-10

a=-2

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Answer 2

Answer:

Let,

f(x) = 2x² + 2ax + 5x +10

(x+a) is a factor of f(x).

so, x + a = 0

or, x = -a

so, f(-a) = 2×(-a)² + 2a×(-a) + 5(-a) +10

= 2a² -2a² - 5a +10

= 10 - 5a

Again, f(-a) = 0

or, 10 - 5a = 0

or, -5a = -10

or, a = 2