Question

22. If xPy9 = (x + y)p+a prove that dy/dx=y/x​

Answer 1

Answer:

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Answer 2

Answer:

Given, x

p

y

q

=(x+y)

p+q

Taking log on both sides, we get

plogx+qlogy=(p+q)log(x+y)

⇒

x

p

+

y

q

dx

dy

=

(x+y)

(p+q)

(1+

dx

dy

)

⇒(

x

p

−

x+y

p+q

)=(

x+y

p+q

−

y

q

)

dx

dy

⇒

dx

dy

=

x

y