22. In a division problem, the divisor is 7
times of quotient and 5 times of remainder.
If the dividend is 6 times of remainder,
then the quotient is equal to
(a) 0
(b)1
(c) 7
(d)None of these
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q=divisor×dividend+remainder
q=31 times of remainder
qoutient=x
divisor=7x
remainder=y
dividend=6y
given that
7x=5y
q=divisor×dividend+remainder
6y×5y+y=quotient
31y=qoutient
there fore qoutient=31 Times of remainder
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