22 In a rectangle ABCD, AC and BD intersect at
O. If <BOC = 40°, find <OBC and <OCB.
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Answer:
In rectangle ABCD
Diagnals of rectangle are congruent bisects each other
AO=OC=OD=OB
In triangle BOC
mBOC=40
BO=OC
therefore triangle BOC is a isosceles triangle
OBC=OCB
measure of all angles of a triangle is 180°
BOC+OBC+OCB=180
40+2OBC=180
OBC =180-40/2
OBC = 70units
OCB=70 UNITS
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