Question

22 In a rectangle ABCD, AC and BD intersect at
O. If <BOC = 40°, find <OBC and <OCB.
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Answer 1

Answer:

In rectangle ABCD

Diagnals of rectangle are congruent bisects each other

AO=OC=OD=OB

In triangle BOC

mBOC=40

BO=OC

therefore triangle BOC is a isosceles triangle

OBC=OCB

measure of all angles of a triangle is 180°

BOC+OBC+OCB=180

40+2OBC=180

OBC =180-40/2

OBC = 70units

OCB=70 UNITS

Step-by-step explanation: