Math, asked by jagrutidhake17, 2 months ago

(22) In “ABC, if AB=BC and angle B= 70°, angle A will be?​

Answers

Answered by Sagar9040
30

Answer:

Angle A = 55°

Step-by-step explanation:

In triangle ABC,

AB = BC

Therefore, triangle ABC is an isosceles triangle.

Therefore, Angle C = Angle A. ( Angle opposite

to equal sides of an isosceles

triangle are equal )

Angle A + Angle B + Angle C = 180°..( Sum of

measure of all angles of a

triangle is 180° )

Angle A + 70° + Angle A= 180°

2*Angle A + 70° = 180°

2*Angle A = 180° - 70°

Angle A = 110° / 2

Therefore, Angle A = 55°

Answered by XxSonaxX
262

Step-by-step explanation:

Question:-

In “ABC, if AB=BC and angle B= 70°, angle A will be?

Answer:-

Given:

In a Δ ABC, AB = AC and ∠B = 70°

∠B = ∠C [Angles opposite to equal sides are equal]

Therefore, ∠B = ∠C = 70°

Sum of angles in a triangle = 180°

∠A + ∠B + ∠C = 180°

∠A + 70° + 70° = 180°

∠A = 180° – 140°

∠A = 40° (Ans)

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