Question

22. In an organic compound of molar mass 108 g
mol", C, H and N atoms are present in the ratio
9:1:35 by weight. The molecular formula of
the organic compound is
a C6H3N2
b) C HioN
c) CsH N3
d) C&H 8N3​

Answer 1

Explanation:

Mass of 1 mole of compound = 108g.

Let the mass of C in 1 mole of compound = 9x.

mass of H in 1 mole of compound = x

mass of N in 1 mole of compound = 3.5x

therefore total mass = 9x+x+3.5x = 13.5x.

According to the question

13.5x=108

=> x=108/13.5 = 8.

mass of C=9x=72g = 12(6)

mass of H= x= 8g = 1(8)

mass of N=3.5x=28g = 14(2)

molar mass of C,H,N = 12, 1, 14.

therefore there are 6, 8, 2 molecules of C,H,N

MOLECULAR FORMULA = C6H8N2.