22. In Hydrogen spectrum electron
comes from 6th energy level to first
energy level in multistep find
maximum number of spectral lines. 2
Your answer
Answers
Answer:
n
2
=6;n
1
=2
n
2
−n
1
=4
Total spectral lines possible =
2
(n
2
−n
1
)[(n
2
−n
1
)+1]
=
2
4×5
=10
No. of Balmer lines possible ⇒
6→2;5→2;4→2;3→2;
Total 4 Balmer lines arfe possible for the given transaction
Expacted spectral line= Total spectral lines possible - No. of Balmer lines possible
= 10−4 = 6
Hence, the correct option is 6.
Explanation:
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Answer:
n
2
=6;n
1
=2
n
2
−n
1
=4
Total spectral lines possible =
2
(n
2
−n
1
)[(n
2
−n
1
)+1]
=
2
4×5
=10
No. of Balmer lines possible ⇒
6→2;5→2;4→2;3→2;
Total 4 Balmer lines arfe possible for the given transaction
Expacted spectral line= Total spectral lines possible - No. of Balmer lines possible
= 10−4 = 6